Eurotec catalogue fastening technology Pagina 211
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Timber engineering KonstruX ST with countersunk head and drill point 6,5 to 10,0 mm: timber/timber joints Dimensions d1 x L [mm] A [mm] B [mm] Extraction resistance Shearing Characteristic value of the joint‘s loadbearing capacity Rax,k acc. to ETA-11/0024 Characteristic value of the joint‘s loadbearing capacity Rax,k acc. to ETA-11/0024 Rax,k a) - [kN] Rk a) - [kN] Rk a) - [kN] Rk a) - [kN] Rk a) - [kN] α= 0° α= 90° αA= 0° αB= 90° αA= 90° αB= 0° 3,47 6,5 x 120 60 80 4,75 3,93 3,47 3,93 6,5 x 140 80 80 4,75 3,93 3,47 3,47 3,93 8,0 x 95 40 60 3,08 4,61 3,57 4,61 3,57 8,0 x 125 60 80 4,61 5,05 4,37 5,05 4,37 8,0 x 155 80 80 7,11 5,67 4,99 4,99 5,67 8,0 x 195 100 100 9,01 6,15 5,46 5,46 6,15 8,0 x 220 120 120 9,48 6,27 5,58 5,58 6,27 8,0 x 245 120 140 11,38 6,74 6,06 6,74 6,06 8,0 x 270 140 140 12,33 6,98 6,29 6,29 6,98 8,0 x 295 140 160 13,28 7,21 6,42 7,21 6,42 8,0 x 330 160 180 15,17 7,69 6,42 7,69 6,42 8,0 x 375 180 200 17,07 7,79 6,42 7,79 6,42 8,0 x 400 200 220 18,97 7,79 6,42 7,79 6,42 8,0 x 430 220 220 19,92 7,79 6,42 6,42 7,79 8,0 x 480 240 260 22,76 7,79 6,42 7,79 6,42 10,0 x 125 60 80 6,92 7,18 6,18 7,18 6,18 10,0 x 155 80 80 8,65 7,61 6,61 6,61 7,61 10,0 x 195 100 100 10,96 8,19 7,19 7,19 8,19 10,0 x 220 120 120 11,53 8,33 7,33 7,33 8,33 10,0 x 245 120 140 13,84 8,91 7,91 8,91 7,91 10,0 x 270 140 140 14,99 9,20 8,20 8,20 9,20 10,0 x 300 160 160 16,15 9,48 8,48 8,48 9,48 10,0 x 330 160 180 18,46 10,06 8,90 10,06 8,90 10,0 x 360 180 200 20,76 10,64 8,90 10,64 8,90 10,0 x 400 200 220 23,07 10,89 8,90 10,89 8,90 10,0 x 450 220 240 25,38 10,89 8,90 10,89 8,90 10,0 x 500 240 280 27,68 10,89 8,90 10,89 8,90 10,0 x 550 260 300 29,99 10,89 8,90 10,89 8,90 10,0 x 600 300 320 33,00 10,89 8,90 10,89 Calculation according to ETA-11/0024. Wood density ρk= 380 kg/m³. All mechanical values provided should be viewed as subject to the assumptions that have been made and represent example calculations. All values are calculated minimum values and are subject to typographical and printing errors. a) The characteristic values of the load-bearing capacity Rk cannot be treated as equivalent to the max. possible load (the max. force). Characteristic values of the load-bearing capacity Rk should be reduced to dimensioning values Rd with regard to the usage class and class of the load duration: Rd= Rk · kmod / γM. The dimensioning values of the load-bearing capacity Rd should be contrasted with the dimensioning values of the loads (Rd ≥ Ed). 8,90 Example: Characteristic value for constant load (dead weight) Gk= 2,00 kN and variable load (e. g. snow load) Qk= 3,00 kN. kmod= 0,9. γM= 1,3. → Dimensioning value of the load Ed= 2,00 · 1,35 + 3,00 · 1,5= 7,20 kN. The load-bearing capacity of the joint is therefore considered to have been demonstrated if Rd ≥ Ed. → min Rk= Rd · γM / kmod . i.e. the characteristic minimum value is calculated based on: min Rk= Rd · γM / kmod → Rk= 7,20 kN · 1,3/0,9= 10,40 kN → comparison with table values. Please note: These are planning aids. Projects must only be calculated by authorised persons. 211
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